The documentation for Python's shutil.make_archive is very confusing. Considering that the arguments to this function only need to be source and destination, makes it even more frustrating to try and reason about.
Here are the relevant docs from the python (2.7) website:
shutil.make_archive(base_name, format[, root_dir[, base_dir[, verbose[, dry_run[, owner[, group[, logger]]]]]]]) Create an archive file (eg. zip or tar) and returns its name. base_name is the name of the file to create, including the path, minus any format-specific extension. format is the archive format: one of “zip” (if the zlib module or external zip executable is available), “tar”, “gztar” (if the zlib module is available), or “bztar” (if the bz2 module is available). root_dir is a directory that will be the root directory of the archive; ie. we typically chdir into root_dir before creating the archive. base_dir is the directory where we start archiving from; ie. base_dir will be the common prefix of all files and directories in the archive. root_dir and base_dir both default to the current directory.
On the face of it they don't seem too bad. Until you try to implement it and nothing seems to work. Took me about 20 permutations of the arguments to get right.. mostly because
base_dir can mean the exact same thing.
Talk about consfusing! Anyway, you can use the following function that I wrote to wrap shutil.make_archive into something more easy to use and understand.
It takes a folder path as the first argument and the destination of archived folder as the second argument.
import os, shutil def make_archive(source, destination): base = os.path.basename(destination) name = base.split('.') format = base.split('.') archive_from = os.path.dirname(source) archive_to = os.path.basename(source.strip(os.sep)) print(source, destination, archive_from, archive_to) shutil.make_archive(name, format, archive_from, archive_to) shutil.move('%s.%s'%(name,format), destination) make_archive('/path/to/folder', '/path/to/folder.zip')